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然后获取比特币

[] int main() { int i = 0, n = 0, sum = 0; printf("请输入N的值\n"); scanf("%d", &n ); for ( i = 1; i < N; i++ ) { sum += i; } printf("%d\n", sum); return 0; }Please enter the value

[] #include<stdio.h> voidmain() { intn,i,sum; printf("请输入n\n") scanf("%d",&n); for(i=1;i<=n;i++) sum+=1/i; printf("和是%f\n",sum); } 扩展资料 求和从1加到n voidmain() { intn,sum=0; printf("inputn:\n"); scanf("%d",n); for(inti=1;i<=n;i++) { sum+=i; } printf("1tonsum=%d",sum); }Please enter and is an extension of the data summation from add to

//因为n不确定,所以最好定义时范围大点,最好是long#include void main() { long n,s,t; s=0; n=1; scanf('%ld',&t); while(n{s=s+n; n=n+1;} printf("1+2+3.....+%ld=%ld\n",t,s); }It's better to have a wide range of definitions because you're not sure

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